Willy Tarreau | c218602 | 2009-10-26 19:48:54 +0100 | [diff] [blame] | 1 | /* |
| 2 | * Elastic Binary Trees - exported functions for operations on 64bit nodes. |
Willy Tarreau | f3bfede | 2011-07-25 11:38:17 +0200 | [diff] [blame] | 3 | * Version 6.0.6 |
| 4 | * (C) 2002-2011 - Willy Tarreau <w@1wt.eu> |
Willy Tarreau | c218602 | 2009-10-26 19:48:54 +0100 | [diff] [blame] | 5 | * |
Willy Tarreau | f3bfede | 2011-07-25 11:38:17 +0200 | [diff] [blame] | 6 | * This library is free software; you can redistribute it and/or |
| 7 | * modify it under the terms of the GNU Lesser General Public |
| 8 | * License as published by the Free Software Foundation, version 2.1 |
| 9 | * exclusively. |
Willy Tarreau | c218602 | 2009-10-26 19:48:54 +0100 | [diff] [blame] | 10 | * |
Willy Tarreau | f3bfede | 2011-07-25 11:38:17 +0200 | [diff] [blame] | 11 | * This library is distributed in the hope that it will be useful, |
Willy Tarreau | c218602 | 2009-10-26 19:48:54 +0100 | [diff] [blame] | 12 | * but WITHOUT ANY WARRANTY; without even the implied warranty of |
Willy Tarreau | f3bfede | 2011-07-25 11:38:17 +0200 | [diff] [blame] | 13 | * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU |
| 14 | * Lesser General Public License for more details. |
Willy Tarreau | c218602 | 2009-10-26 19:48:54 +0100 | [diff] [blame] | 15 | * |
Willy Tarreau | f3bfede | 2011-07-25 11:38:17 +0200 | [diff] [blame] | 16 | * You should have received a copy of the GNU Lesser General Public |
| 17 | * License along with this library; if not, write to the Free Software |
| 18 | * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA |
Willy Tarreau | c218602 | 2009-10-26 19:48:54 +0100 | [diff] [blame] | 19 | */ |
| 20 | |
| 21 | /* Consult eb64tree.h for more details about those functions */ |
| 22 | |
| 23 | #include "eb64tree.h" |
| 24 | |
| 25 | REGPRM2 struct eb64_node *eb64_insert(struct eb_root *root, struct eb64_node *new) |
| 26 | { |
| 27 | return __eb64_insert(root, new); |
| 28 | } |
| 29 | |
| 30 | REGPRM2 struct eb64_node *eb64i_insert(struct eb_root *root, struct eb64_node *new) |
| 31 | { |
| 32 | return __eb64i_insert(root, new); |
| 33 | } |
| 34 | |
| 35 | REGPRM2 struct eb64_node *eb64_lookup(struct eb_root *root, u64 x) |
| 36 | { |
| 37 | return __eb64_lookup(root, x); |
| 38 | } |
| 39 | |
| 40 | REGPRM2 struct eb64_node *eb64i_lookup(struct eb_root *root, s64 x) |
| 41 | { |
| 42 | return __eb64i_lookup(root, x); |
| 43 | } |
| 44 | |
| 45 | /* |
| 46 | * Find the last occurrence of the highest key in the tree <root>, which is |
| 47 | * equal to or less than <x>. NULL is returned is no key matches. |
| 48 | */ |
| 49 | REGPRM2 struct eb64_node *eb64_lookup_le(struct eb_root *root, u64 x) |
| 50 | { |
| 51 | struct eb64_node *node; |
| 52 | eb_troot_t *troot; |
| 53 | |
| 54 | troot = root->b[EB_LEFT]; |
| 55 | if (unlikely(troot == NULL)) |
| 56 | return NULL; |
| 57 | |
| 58 | while (1) { |
| 59 | if ((eb_gettag(troot) == EB_LEAF)) { |
| 60 | /* We reached a leaf, which means that the whole upper |
| 61 | * parts were common. We will return either the current |
| 62 | * node or its next one if the former is too small. |
| 63 | */ |
| 64 | node = container_of(eb_untag(troot, EB_LEAF), |
| 65 | struct eb64_node, node.branches); |
| 66 | if (node->key <= x) |
| 67 | return node; |
| 68 | /* return prev */ |
| 69 | troot = node->node.leaf_p; |
| 70 | break; |
| 71 | } |
| 72 | node = container_of(eb_untag(troot, EB_NODE), |
| 73 | struct eb64_node, node.branches); |
| 74 | |
| 75 | if (node->node.bit < 0) { |
| 76 | /* We're at the top of a dup tree. Either we got a |
| 77 | * matching value and we return the rightmost node, or |
| 78 | * we don't and we skip the whole subtree to return the |
| 79 | * prev node before the subtree. Note that since we're |
| 80 | * at the top of the dup tree, we can simply return the |
| 81 | * prev node without first trying to escape from the |
| 82 | * tree. |
| 83 | */ |
| 84 | if (node->key <= x) { |
| 85 | troot = node->node.branches.b[EB_RGHT]; |
| 86 | while (eb_gettag(troot) != EB_LEAF) |
| 87 | troot = (eb_untag(troot, EB_NODE))->b[EB_RGHT]; |
| 88 | return container_of(eb_untag(troot, EB_LEAF), |
| 89 | struct eb64_node, node.branches); |
| 90 | } |
| 91 | /* return prev */ |
| 92 | troot = node->node.node_p; |
| 93 | break; |
| 94 | } |
| 95 | |
| 96 | if (((x ^ node->key) >> node->node.bit) >= EB_NODE_BRANCHES) { |
| 97 | /* No more common bits at all. Either this node is too |
| 98 | * small and we need to get its highest value, or it is |
| 99 | * too large, and we need to get the prev value. |
| 100 | */ |
Willy Tarreau | 3a93244 | 2010-05-09 19:29:23 +0200 | [diff] [blame] | 101 | if ((node->key >> node->node.bit) < (x >> node->node.bit)) { |
Willy Tarreau | c218602 | 2009-10-26 19:48:54 +0100 | [diff] [blame] | 102 | troot = node->node.branches.b[EB_RGHT]; |
| 103 | return eb64_entry(eb_walk_down(troot, EB_RGHT), struct eb64_node, node); |
| 104 | } |
| 105 | |
| 106 | /* Further values will be too high here, so return the prev |
| 107 | * unique node (if it exists). |
| 108 | */ |
| 109 | troot = node->node.node_p; |
| 110 | break; |
| 111 | } |
| 112 | troot = node->node.branches.b[(x >> node->node.bit) & EB_NODE_BRANCH_MASK]; |
| 113 | } |
| 114 | |
| 115 | /* If we get here, it means we want to report previous node before the |
| 116 | * current one which is not above. <troot> is already initialised to |
| 117 | * the parent's branches. |
| 118 | */ |
| 119 | while (eb_gettag(troot) == EB_LEFT) { |
| 120 | /* Walking up from left branch. We must ensure that we never |
| 121 | * walk beyond root. |
| 122 | */ |
| 123 | if (unlikely(eb_clrtag((eb_untag(troot, EB_LEFT))->b[EB_RGHT]) == NULL)) |
| 124 | return NULL; |
| 125 | troot = (eb_root_to_node(eb_untag(troot, EB_LEFT)))->node_p; |
| 126 | } |
| 127 | /* Note that <troot> cannot be NULL at this stage */ |
| 128 | troot = (eb_untag(troot, EB_RGHT))->b[EB_LEFT]; |
| 129 | node = eb64_entry(eb_walk_down(troot, EB_RGHT), struct eb64_node, node); |
| 130 | return node; |
| 131 | } |
| 132 | |
| 133 | /* |
| 134 | * Find the first occurrence of the lowest key in the tree <root>, which is |
| 135 | * equal to or greater than <x>. NULL is returned is no key matches. |
| 136 | */ |
| 137 | REGPRM2 struct eb64_node *eb64_lookup_ge(struct eb_root *root, u64 x) |
| 138 | { |
| 139 | struct eb64_node *node; |
| 140 | eb_troot_t *troot; |
| 141 | |
| 142 | troot = root->b[EB_LEFT]; |
| 143 | if (unlikely(troot == NULL)) |
| 144 | return NULL; |
| 145 | |
| 146 | while (1) { |
| 147 | if ((eb_gettag(troot) == EB_LEAF)) { |
| 148 | /* We reached a leaf, which means that the whole upper |
| 149 | * parts were common. We will return either the current |
| 150 | * node or its next one if the former is too small. |
| 151 | */ |
| 152 | node = container_of(eb_untag(troot, EB_LEAF), |
| 153 | struct eb64_node, node.branches); |
| 154 | if (node->key >= x) |
| 155 | return node; |
| 156 | /* return next */ |
| 157 | troot = node->node.leaf_p; |
| 158 | break; |
| 159 | } |
| 160 | node = container_of(eb_untag(troot, EB_NODE), |
| 161 | struct eb64_node, node.branches); |
| 162 | |
| 163 | if (node->node.bit < 0) { |
| 164 | /* We're at the top of a dup tree. Either we got a |
| 165 | * matching value and we return the leftmost node, or |
| 166 | * we don't and we skip the whole subtree to return the |
| 167 | * next node after the subtree. Note that since we're |
| 168 | * at the top of the dup tree, we can simply return the |
| 169 | * next node without first trying to escape from the |
| 170 | * tree. |
| 171 | */ |
| 172 | if (node->key >= x) { |
| 173 | troot = node->node.branches.b[EB_LEFT]; |
| 174 | while (eb_gettag(troot) != EB_LEAF) |
| 175 | troot = (eb_untag(troot, EB_NODE))->b[EB_LEFT]; |
| 176 | return container_of(eb_untag(troot, EB_LEAF), |
| 177 | struct eb64_node, node.branches); |
| 178 | } |
| 179 | /* return next */ |
| 180 | troot = node->node.node_p; |
| 181 | break; |
| 182 | } |
| 183 | |
| 184 | if (((x ^ node->key) >> node->node.bit) >= EB_NODE_BRANCHES) { |
| 185 | /* No more common bits at all. Either this node is too |
| 186 | * large and we need to get its lowest value, or it is too |
| 187 | * small, and we need to get the next value. |
| 188 | */ |
| 189 | if ((node->key >> node->node.bit) > (x >> node->node.bit)) { |
| 190 | troot = node->node.branches.b[EB_LEFT]; |
| 191 | return eb64_entry(eb_walk_down(troot, EB_LEFT), struct eb64_node, node); |
| 192 | } |
| 193 | |
| 194 | /* Further values will be too low here, so return the next |
| 195 | * unique node (if it exists). |
| 196 | */ |
| 197 | troot = node->node.node_p; |
| 198 | break; |
| 199 | } |
| 200 | troot = node->node.branches.b[(x >> node->node.bit) & EB_NODE_BRANCH_MASK]; |
| 201 | } |
| 202 | |
| 203 | /* If we get here, it means we want to report next node after the |
| 204 | * current one which is not below. <troot> is already initialised |
| 205 | * to the parent's branches. |
| 206 | */ |
| 207 | while (eb_gettag(troot) != EB_LEFT) |
| 208 | /* Walking up from right branch, so we cannot be below root */ |
| 209 | troot = (eb_root_to_node(eb_untag(troot, EB_RGHT)))->node_p; |
| 210 | |
| 211 | /* Note that <troot> cannot be NULL at this stage */ |
| 212 | troot = (eb_untag(troot, EB_LEFT))->b[EB_RGHT]; |
| 213 | if (eb_clrtag(troot) == NULL) |
| 214 | return NULL; |
| 215 | |
| 216 | node = eb64_entry(eb_walk_down(troot, EB_LEFT), struct eb64_node, node); |
| 217 | return node; |
| 218 | } |