| /* |
| * Elastic Binary Trees - macros and structures for Multi-Byte data nodes. |
| * Version 6.0.1 |
| * (C) 2002-2010 - Willy Tarreau <w@1wt.eu> |
| * |
| * This program is free software; you can redistribute it and/or modify |
| * it under the terms of the GNU General Public License as published by |
| * the Free Software Foundation; either version 2 of the License, or |
| * (at your option) any later version. |
| * |
| * This program is distributed in the hope that it will be useful, |
| * but WITHOUT ANY WARRANTY; without even the implied warranty of |
| * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the |
| * GNU General Public License for more details. |
| * |
| * You should have received a copy of the GNU General Public License |
| * along with this program; if not, write to the Free Software |
| * Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA |
| */ |
| |
| #ifndef _EBMBTREE_H |
| #define _EBMBTREE_H |
| |
| #include <string.h> |
| #include "ebtree.h" |
| |
| /* Return the structure of type <type> whose member <member> points to <ptr> */ |
| #define ebmb_entry(ptr, type, member) container_of(ptr, type, member) |
| |
| #define EBMB_ROOT EB_ROOT |
| #define EBMB_TREE_HEAD EB_TREE_HEAD |
| |
| /* This structure carries a node, a leaf, and a key. It must start with the |
| * eb_node so that it can be cast into an eb_node. We could also have put some |
| * sort of transparent union here to reduce the indirection level, but the fact |
| * is, the end user is not meant to manipulate internals, so this is pointless. |
| * The 'node.bit' value here works differently from scalar types, as it contains |
| * the number of identical bits between the two branches. |
| */ |
| struct ebmb_node { |
| struct eb_node node; /* the tree node, must be at the beginning */ |
| unsigned char key[0]; /* the key, its size depends on the application */ |
| }; |
| |
| /* |
| * Exported functions and macros. |
| * Many of them are always inlined because they are extremely small, and |
| * are generally called at most once or twice in a program. |
| */ |
| |
| /* Return leftmost node in the tree, or NULL if none */ |
| static forceinline struct ebmb_node *ebmb_first(struct eb_root *root) |
| { |
| return ebmb_entry(eb_first(root), struct ebmb_node, node); |
| } |
| |
| /* Return rightmost node in the tree, or NULL if none */ |
| static forceinline struct ebmb_node *ebmb_last(struct eb_root *root) |
| { |
| return ebmb_entry(eb_last(root), struct ebmb_node, node); |
| } |
| |
| /* Return next node in the tree, or NULL if none */ |
| static forceinline struct ebmb_node *ebmb_next(struct ebmb_node *ebmb) |
| { |
| return ebmb_entry(eb_next(&ebmb->node), struct ebmb_node, node); |
| } |
| |
| /* Return previous node in the tree, or NULL if none */ |
| static forceinline struct ebmb_node *ebmb_prev(struct ebmb_node *ebmb) |
| { |
| return ebmb_entry(eb_prev(&ebmb->node), struct ebmb_node, node); |
| } |
| |
| /* Return next node in the tree, skipping duplicates, or NULL if none */ |
| static forceinline struct ebmb_node *ebmb_next_unique(struct ebmb_node *ebmb) |
| { |
| return ebmb_entry(eb_next_unique(&ebmb->node), struct ebmb_node, node); |
| } |
| |
| /* Return previous node in the tree, skipping duplicates, or NULL if none */ |
| static forceinline struct ebmb_node *ebmb_prev_unique(struct ebmb_node *ebmb) |
| { |
| return ebmb_entry(eb_prev_unique(&ebmb->node), struct ebmb_node, node); |
| } |
| |
| /* Delete node from the tree if it was linked in. Mark the node unused. Note |
| * that this function relies on a non-inlined generic function: eb_delete. |
| */ |
| static forceinline void ebmb_delete(struct ebmb_node *ebmb) |
| { |
| eb_delete(&ebmb->node); |
| } |
| |
| /* The following functions are not inlined by default. They are declared |
| * in ebmbtree.c, which simply relies on their inline version. |
| */ |
| REGPRM3 struct ebmb_node *ebmb_lookup(struct eb_root *root, const void *x, unsigned int len); |
| REGPRM3 struct ebmb_node *ebmb_insert(struct eb_root *root, struct ebmb_node *new, unsigned int len); |
| REGPRM2 struct ebmb_node *ebmb_lookup_longest(struct eb_root *root, const void *x); |
| REGPRM3 struct ebmb_node *ebmb_lookup_prefix(struct eb_root *root, const void *x, unsigned int pfx); |
| REGPRM3 struct ebmb_node *ebmb_insert_prefix(struct eb_root *root, struct ebmb_node *new, unsigned int len); |
| |
| /* The following functions are less likely to be used directly, because their |
| * code is larger. The non-inlined version is preferred. |
| */ |
| |
| /* Delete node from the tree if it was linked in. Mark the node unused. */ |
| static forceinline void __ebmb_delete(struct ebmb_node *ebmb) |
| { |
| __eb_delete(&ebmb->node); |
| } |
| |
| /* Find the first occurence of a key of <len> bytes in the tree <root>. |
| * If none can be found, return NULL. |
| */ |
| static forceinline struct ebmb_node *__ebmb_lookup(struct eb_root *root, const void *x, unsigned int len) |
| { |
| struct ebmb_node *node; |
| eb_troot_t *troot; |
| int pos, side; |
| int node_bit; |
| |
| troot = root->b[EB_LEFT]; |
| if (unlikely(troot == NULL)) |
| return NULL; |
| |
| pos = 0; |
| while (1) { |
| if (eb_gettag(troot) == EB_LEAF) { |
| node = container_of(eb_untag(troot, EB_LEAF), |
| struct ebmb_node, node.branches); |
| if (memcmp(node->key + pos, x, len - pos) != 0) |
| return NULL; |
| else |
| return node; |
| } |
| node = container_of(eb_untag(troot, EB_NODE), |
| struct ebmb_node, node.branches); |
| |
| node_bit = node->node.bit; |
| if (node_bit < 0) { |
| /* We have a dup tree now. Either it's for the same |
| * value, and we walk down left, or it's a different |
| * one and we don't have our key. |
| */ |
| if (memcmp(node->key + pos, x, len - pos) != 0) |
| return NULL; |
| |
| troot = node->node.branches.b[EB_LEFT]; |
| while (eb_gettag(troot) != EB_LEAF) |
| troot = (eb_untag(troot, EB_NODE))->b[EB_LEFT]; |
| node = container_of(eb_untag(troot, EB_LEAF), |
| struct ebmb_node, node.branches); |
| return node; |
| } |
| |
| /* OK, normal data node, let's walk down. We check if all full |
| * bytes are equal, and we start from the last one we did not |
| * completely check. We stop as soon as we reach the last byte, |
| * because we must decide to go left/right or abort. |
| */ |
| node_bit = ~node_bit + (pos << 3) + 8; // = (pos<<3) + (7 - node_bit) |
| if (node_bit < 0) { |
| /* This surprizing construction gives better performance |
| * because gcc does not try to reorder the loop. Tested to |
| * be fine with 2.95 to 4.2. |
| */ |
| while (1) { |
| x++; pos++; |
| if (node->key[pos-1] ^ *(unsigned char*)(x-1)) |
| return NULL; /* more than one full byte is different */ |
| node_bit += 8; |
| if (node_bit >= 0) |
| break; |
| } |
| } |
| |
| /* here we know that only the last byte differs, so node_bit < 8. |
| * We have 2 possibilities : |
| * - more than the last bit differs => return NULL |
| * - walk down on side = (x[pos] >> node_bit) & 1 |
| */ |
| side = *(unsigned char *)x >> node_bit; |
| if (((node->key[pos] >> node_bit) ^ side) > 1) |
| return NULL; |
| side &= 1; |
| troot = node->node.branches.b[side]; |
| } |
| } |
| |
| /* Insert ebmb_node <new> into subtree starting at node root <root>. |
| * Only new->key needs be set with the key. The ebmb_node is returned. |
| * If root->b[EB_RGHT]==1, the tree may only contain unique keys. The |
| * len is specified in bytes. |
| */ |
| static forceinline struct ebmb_node * |
| __ebmb_insert(struct eb_root *root, struct ebmb_node *new, unsigned int len) |
| { |
| struct ebmb_node *old; |
| unsigned int side; |
| eb_troot_t *troot, **up_ptr; |
| eb_troot_t *root_right = root; |
| int diff; |
| int bit; |
| eb_troot_t *new_left, *new_rght; |
| eb_troot_t *new_leaf; |
| int old_node_bit; |
| |
| side = EB_LEFT; |
| troot = root->b[EB_LEFT]; |
| root_right = root->b[EB_RGHT]; |
| if (unlikely(troot == NULL)) { |
| /* Tree is empty, insert the leaf part below the left branch */ |
| root->b[EB_LEFT] = eb_dotag(&new->node.branches, EB_LEAF); |
| new->node.leaf_p = eb_dotag(root, EB_LEFT); |
| new->node.node_p = NULL; /* node part unused */ |
| return new; |
| } |
| |
| /* The tree descent is fairly easy : |
| * - first, check if we have reached a leaf node |
| * - second, check if we have gone too far |
| * - third, reiterate |
| * Everywhere, we use <new> for the node node we are inserting, <root> |
| * for the node we attach it to, and <old> for the node we are |
| * displacing below <new>. <troot> will always point to the future node |
| * (tagged with its type). <side> carries the side the node <new> is |
| * attached to below its parent, which is also where previous node |
| * was attached. |
| */ |
| |
| bit = 0; |
| while (1) { |
| if (unlikely(eb_gettag(troot) == EB_LEAF)) { |
| /* insert above a leaf */ |
| old = container_of(eb_untag(troot, EB_LEAF), |
| struct ebmb_node, node.branches); |
| new->node.node_p = old->node.leaf_p; |
| up_ptr = &old->node.leaf_p; |
| goto check_bit_and_break; |
| } |
| |
| /* OK we're walking down this link */ |
| old = container_of(eb_untag(troot, EB_NODE), |
| struct ebmb_node, node.branches); |
| old_node_bit = old->node.bit; |
| |
| if (unlikely(old->node.bit < 0)) { |
| /* We're above a duplicate tree, so we must compare the whole value */ |
| new->node.node_p = old->node.node_p; |
| up_ptr = &old->node.node_p; |
| check_bit_and_break: |
| bit = equal_bits(new->key, old->key, bit, len << 3); |
| break; |
| } |
| |
| /* Stop going down when we don't have common bits anymore. We |
| * also stop in front of a duplicates tree because it means we |
| * have to insert above. Note: we can compare more bits than |
| * the current node's because as long as they are identical, we |
| * know we descend along the correct side. |
| */ |
| |
| bit = equal_bits(new->key, old->key, bit, old_node_bit); |
| if (unlikely(bit < old_node_bit)) { |
| /* The tree did not contain the key, so we insert <new> before the |
| * node <old>, and set ->bit to designate the lowest bit position in |
| * <new> which applies to ->branches.b[]. |
| */ |
| new->node.node_p = old->node.node_p; |
| up_ptr = &old->node.node_p; |
| break; |
| } |
| /* we don't want to skip bits for further comparisons, so we must limit <bit>. |
| * However, since we're going down around <old_node_bit>, we know it will be |
| * properly matched, so we can skip this bit. |
| */ |
| bit = old_node_bit + 1; |
| |
| /* walk down */ |
| root = &old->node.branches; |
| side = old_node_bit & 7; |
| side ^= 7; |
| side = (new->key[old_node_bit >> 3] >> side) & 1; |
| troot = root->b[side]; |
| } |
| |
| new_left = eb_dotag(&new->node.branches, EB_LEFT); |
| new_rght = eb_dotag(&new->node.branches, EB_RGHT); |
| new_leaf = eb_dotag(&new->node.branches, EB_LEAF); |
| |
| /* Note: we can compare more bits than |
| * the current node's because as long as they are identical, we |
| * know we descend along the correct side. |
| */ |
| new->node.bit = bit; |
| diff = cmp_bits(new->key, old->key, bit); |
| if (diff == 0) { |
| new->node.bit = -1; /* mark as new dup tree, just in case */ |
| |
| if (likely(eb_gettag(root_right))) { |
| /* we refuse to duplicate this key if the tree is |
| * tagged as containing only unique keys. |
| */ |
| return old; |
| } |
| |
| if (eb_gettag(troot) != EB_LEAF) { |
| /* there was already a dup tree below */ |
| struct eb_node *ret; |
| ret = eb_insert_dup(&old->node, &new->node); |
| return container_of(ret, struct ebmb_node, node); |
| } |
| /* otherwise fall through */ |
| } |
| |
| if (diff >= 0) { |
| new->node.branches.b[EB_LEFT] = troot; |
| new->node.branches.b[EB_RGHT] = new_leaf; |
| new->node.leaf_p = new_rght; |
| *up_ptr = new_left; |
| } |
| else if (diff < 0) { |
| new->node.branches.b[EB_LEFT] = new_leaf; |
| new->node.branches.b[EB_RGHT] = troot; |
| new->node.leaf_p = new_left; |
| *up_ptr = new_rght; |
| } |
| |
| /* Ok, now we are inserting <new> between <root> and <old>. <old>'s |
| * parent is already set to <new>, and the <root>'s branch is still in |
| * <side>. Update the root's leaf till we have it. Note that we can also |
| * find the side by checking the side of new->node.node_p. |
| */ |
| |
| root->b[side] = eb_dotag(&new->node.branches, EB_NODE); |
| return new; |
| } |
| |
| |
| /* Find the first occurence of the longest prefix matching a key <x> in the |
| * tree <root>. It's the caller's responsibility to ensure that key <x> is at |
| * least as long as the keys in the tree. If none can be found, return NULL. |
| */ |
| static forceinline struct ebmb_node *__ebmb_lookup_longest(struct eb_root *root, const void *x) |
| { |
| struct ebmb_node *node; |
| eb_troot_t *troot, *cover; |
| int pos, side; |
| int node_bit; |
| |
| troot = root->b[EB_LEFT]; |
| if (unlikely(troot == NULL)) |
| return NULL; |
| |
| cover = NULL; |
| pos = 0; |
| while (1) { |
| if ((eb_gettag(troot) == EB_LEAF)) { |
| node = container_of(eb_untag(troot, EB_LEAF), |
| struct ebmb_node, node.branches); |
| if (check_bits(x - pos, node->key, pos, node->node.pfx)) |
| goto not_found; |
| |
| return node; |
| } |
| node = container_of(eb_untag(troot, EB_NODE), |
| struct ebmb_node, node.branches); |
| |
| node_bit = node->node.bit; |
| if (node_bit < 0) { |
| /* We have a dup tree now. Either it's for the same |
| * value, and we walk down left, or it's a different |
| * one and we don't have our key. |
| */ |
| if (check_bits(x - pos, node->key, pos, node->node.pfx)) |
| goto not_found; |
| |
| troot = node->node.branches.b[EB_LEFT]; |
| while (eb_gettag(troot) != EB_LEAF) |
| troot = (eb_untag(troot, EB_NODE))->b[EB_LEFT]; |
| node = container_of(eb_untag(troot, EB_LEAF), |
| struct ebmb_node, node.branches); |
| return node; |
| } |
| |
| node_bit >>= 1; /* strip cover bit */ |
| node_bit = ~node_bit + (pos << 3) + 8; // = (pos<<3) + (7 - node_bit) |
| if (node_bit < 0) { |
| /* This uncommon construction gives better performance |
| * because gcc does not try to reorder the loop. Tested to |
| * be fine with 2.95 to 4.2. |
| */ |
| while (1) { |
| x++; pos++; |
| if (node->key[pos-1] ^ *(unsigned char*)(x-1)) |
| goto not_found; /* more than one full byte is different */ |
| node_bit += 8; |
| if (node_bit >= 0) |
| break; |
| } |
| } |
| |
| /* here we know that only the last byte differs, so 0 <= node_bit <= 7. |
| * We have 2 possibilities : |
| * - more than the last bit differs => data does not match |
| * - walk down on side = (x[pos] >> node_bit) & 1 |
| */ |
| side = *(unsigned char *)x >> node_bit; |
| if (((node->key[pos] >> node_bit) ^ side) > 1) |
| goto not_found; |
| |
| if (!(node->node.bit & 1)) { |
| /* This is a cover node, let's keep a reference to it |
| * for later. The covering subtree is on the left, and |
| * the covered subtree is on the right, so we have to |
| * walk down right. |
| */ |
| cover = node->node.branches.b[EB_LEFT]; |
| troot = node->node.branches.b[EB_RGHT]; |
| continue; |
| } |
| side &= 1; |
| troot = node->node.branches.b[side]; |
| } |
| |
| not_found: |
| /* Walk down last cover tre if it exists. It does not matter if cover is NULL */ |
| return ebmb_entry(eb_walk_down(cover, EB_LEFT), struct ebmb_node, node); |
| } |
| |
| |
| /* Find the first occurence of a prefix matching a key <x> of <pfx> BITS in the |
| * tree <root>. If none can be found, return NULL. |
| */ |
| static forceinline struct ebmb_node *__ebmb_lookup_prefix(struct eb_root *root, const void *x, unsigned int pfx) |
| { |
| struct ebmb_node *node; |
| eb_troot_t *troot; |
| int pos, side; |
| int node_bit; |
| |
| troot = root->b[EB_LEFT]; |
| if (unlikely(troot == NULL)) |
| return NULL; |
| |
| pos = 0; |
| while (1) { |
| if ((eb_gettag(troot) == EB_LEAF)) { |
| node = container_of(eb_untag(troot, EB_LEAF), |
| struct ebmb_node, node.branches); |
| if (node->node.pfx != pfx) |
| return NULL; |
| if (check_bits(x - pos, node->key, pos, node->node.pfx)) |
| return NULL; |
| return node; |
| } |
| node = container_of(eb_untag(troot, EB_NODE), |
| struct ebmb_node, node.branches); |
| |
| node_bit = node->node.bit; |
| if (node_bit < 0) { |
| /* We have a dup tree now. Either it's for the same |
| * value, and we walk down left, or it's a different |
| * one and we don't have our key. |
| */ |
| if (node->node.pfx != pfx) |
| return NULL; |
| if (check_bits(x - pos, node->key, pos, node->node.pfx)) |
| return NULL; |
| |
| troot = node->node.branches.b[EB_LEFT]; |
| while (eb_gettag(troot) != EB_LEAF) |
| troot = (eb_untag(troot, EB_NODE))->b[EB_LEFT]; |
| node = container_of(eb_untag(troot, EB_LEAF), |
| struct ebmb_node, node.branches); |
| return node; |
| } |
| |
| node_bit >>= 1; /* strip cover bit */ |
| node_bit = ~node_bit + (pos << 3) + 8; // = (pos<<3) + (7 - node_bit) |
| if (node_bit < 0) { |
| /* This uncommon construction gives better performance |
| * because gcc does not try to reorder the loop. Tested to |
| * be fine with 2.95 to 4.2. |
| */ |
| while (1) { |
| x++; pos++; |
| if (node->key[pos-1] ^ *(unsigned char*)(x-1)) |
| return NULL; /* more than one full byte is different */ |
| node_bit += 8; |
| if (node_bit >= 0) |
| break; |
| } |
| } |
| |
| /* here we know that only the last byte differs, so 0 <= node_bit <= 7. |
| * We have 2 possibilities : |
| * - more than the last bit differs => data does not match |
| * - walk down on side = (x[pos] >> node_bit) & 1 |
| */ |
| side = *(unsigned char *)x >> node_bit; |
| if (((node->key[pos] >> node_bit) ^ side) > 1) |
| return NULL; |
| |
| if (!(node->node.bit & 1)) { |
| /* This is a cover node, it may be the entry we're |
| * looking for. We already know that it matches all the |
| * bits, let's compare prefixes and descend the cover |
| * subtree if they match. |
| */ |
| if (node->node.bit >> 1 == pfx) |
| troot = node->node.branches.b[EB_LEFT]; |
| else |
| troot = node->node.branches.b[EB_RGHT]; |
| continue; |
| } |
| side &= 1; |
| troot = node->node.branches.b[side]; |
| } |
| } |
| |
| |
| /* Insert ebmb_node <new> into a prefix subtree starting at node root <root>. |
| * Only new->key and new->pfx need be set with the key and its prefix length. |
| * Note that bits between <pfx> and <len> are theorically ignored and should be |
| * zero, as it is not certain yet that they will always be ignored everywhere |
| * (eg in bit compare functions). |
| * The ebmb_node is returned. |
| * If root->b[EB_RGHT]==1, the tree may only contain unique keys. The |
| * len is specified in bytes. |
| */ |
| static forceinline struct ebmb_node * |
| __ebmb_insert_prefix(struct eb_root *root, struct ebmb_node *new, unsigned int len) |
| { |
| struct ebmb_node *old; |
| unsigned int side; |
| eb_troot_t *troot, **up_ptr; |
| eb_troot_t *root_right = root; |
| int diff; |
| int bit; |
| eb_troot_t *new_left, *new_rght; |
| eb_troot_t *new_leaf; |
| int old_node_bit; |
| |
| side = EB_LEFT; |
| troot = root->b[EB_LEFT]; |
| root_right = root->b[EB_RGHT]; |
| if (unlikely(troot == NULL)) { |
| /* Tree is empty, insert the leaf part below the left branch */ |
| root->b[EB_LEFT] = eb_dotag(&new->node.branches, EB_LEAF); |
| new->node.leaf_p = eb_dotag(root, EB_LEFT); |
| new->node.node_p = NULL; /* node part unused */ |
| return new; |
| } |
| |
| len <<= 3; |
| if (len > new->node.pfx) |
| len = new->node.pfx; |
| |
| /* The tree descent is fairly easy : |
| * - first, check if we have reached a leaf node |
| * - second, check if we have gone too far |
| * - third, reiterate |
| * Everywhere, we use <new> for the node node we are inserting, <root> |
| * for the node we attach it to, and <old> for the node we are |
| * displacing below <new>. <troot> will always point to the future node |
| * (tagged with its type). <side> carries the side the node <new> is |
| * attached to below its parent, which is also where previous node |
| * was attached. |
| */ |
| |
| bit = 0; |
| while (1) { |
| if (unlikely(eb_gettag(troot) == EB_LEAF)) { |
| /* Insert above a leaf. Note that this leaf could very |
| * well be part of a cover node. |
| */ |
| old = container_of(eb_untag(troot, EB_LEAF), |
| struct ebmb_node, node.branches); |
| new->node.node_p = old->node.leaf_p; |
| up_ptr = &old->node.leaf_p; |
| goto check_bit_and_break; |
| } |
| |
| /* OK we're walking down this link */ |
| old = container_of(eb_untag(troot, EB_NODE), |
| struct ebmb_node, node.branches); |
| old_node_bit = old->node.bit; |
| /* Note that old_node_bit can be : |
| * < 0 : dup tree |
| * = 2N : cover node for N bits |
| * = 2N+1 : normal node at N bits |
| */ |
| |
| if (unlikely(old_node_bit < 0)) { |
| /* We're above a duplicate tree, so we must compare the whole value */ |
| new->node.node_p = old->node.node_p; |
| up_ptr = &old->node.node_p; |
| check_bit_and_break: |
| /* No need to compare everything if the leaves are shorter than the new one. */ |
| if (len > old->node.pfx) |
| len = old->node.pfx; |
| bit = equal_bits(new->key, old->key, bit, len); |
| break; |
| } |
| |
| /* WARNING: for the two blocks below, <bit> is counted in half-bits */ |
| |
| bit = equal_bits(new->key, old->key, bit, old_node_bit >> 1); |
| bit = (bit << 1) + 1; // assume comparisons with normal nodes |
| |
| /* we must always check that our prefix is larger than the nodes |
| * we visit, otherwise we have to stop going down. The following |
| * test is able to stop before both normal and cover nodes. |
| */ |
| if (bit >= (new->node.pfx << 1) && (new->node.pfx << 1) < old_node_bit) { |
| /* insert cover node here on the left */ |
| new->node.node_p = old->node.node_p; |
| up_ptr = &old->node.node_p; |
| new->node.bit = new->node.pfx << 1; |
| diff = -1; |
| goto insert_above; |
| } |
| |
| if (unlikely(bit < old_node_bit)) { |
| /* The tree did not contain the key, so we insert <new> before the |
| * node <old>, and set ->bit to designate the lowest bit position in |
| * <new> which applies to ->branches.b[]. We know that the bit is not |
| * greater than the prefix length thanks to the test above. |
| */ |
| new->node.node_p = old->node.node_p; |
| up_ptr = &old->node.node_p; |
| new->node.bit = bit; |
| diff = cmp_bits(new->key, old->key, bit >> 1); |
| goto insert_above; |
| } |
| |
| if (!(old_node_bit & 1)) { |
| /* if we encounter a cover node with our exact prefix length, it's |
| * necessarily the same value, so we insert there as a duplicate on |
| * the left. For that, we go down on the left and the leaf detection |
| * code will finish the job. |
| */ |
| if ((new->node.pfx << 1) == old_node_bit) { |
| root = &old->node.branches; |
| side = EB_LEFT; |
| troot = root->b[side]; |
| continue; |
| } |
| |
| /* cover nodes are always walked through on the right */ |
| side = EB_RGHT; |
| bit = old_node_bit >> 1; /* recheck that bit */ |
| root = &old->node.branches; |
| troot = root->b[side]; |
| continue; |
| } |
| |
| /* we don't want to skip bits for further comparisons, so we must limit <bit>. |
| * However, since we're going down around <old_node_bit>, we know it will be |
| * properly matched, so we can skip this bit. |
| */ |
| old_node_bit >>= 1; |
| bit = old_node_bit + 1; |
| |
| /* walk down */ |
| root = &old->node.branches; |
| side = old_node_bit & 7; |
| side ^= 7; |
| side = (new->key[old_node_bit >> 3] >> side) & 1; |
| troot = root->b[side]; |
| } |
| |
| /* Right here, we have 4 possibilities : |
| * - the tree does not contain any leaf matching the |
| * key, and we have new->key < old->key. We insert |
| * new above old, on the left ; |
| * |
| * - the tree does not contain any leaf matching the |
| * key, and we have new->key > old->key. We insert |
| * new above old, on the right ; |
| * |
| * - the tree does contain the key with the same prefix |
| * length. We add the new key next to it as a first |
| * duplicate (since it was alone). |
| * |
| * The last two cases can easily be partially merged. |
| * |
| * - the tree contains a leaf matching the key, we have |
| * to insert above it as a cover node. The leaf with |
| * the shortest prefix becomes the left subtree and |
| * the leaf with the longest prefix becomes the right |
| * one. The cover node gets the min of both prefixes |
| * as its new bit. |
| */ |
| |
| /* first we want to ensure that we compare the correct bit, which means |
| * the largest common to both nodes. |
| */ |
| if (bit > new->node.pfx) |
| bit = new->node.pfx; |
| if (bit > old->node.pfx) |
| bit = old->node.pfx; |
| |
| new->node.bit = (bit << 1) + 1; /* assume normal node by default */ |
| |
| /* if one prefix is included in the second one, we don't compare bits |
| * because they won't necessarily match, we just proceed with a cover |
| * node insertion. |
| */ |
| diff = 0; |
| if (bit < old->node.pfx && bit < new->node.pfx) |
| diff = cmp_bits(new->key, old->key, bit); |
| |
| if (diff == 0) { |
| /* Both keys match. Either it's a duplicate entry or we have to |
| * put the shortest prefix left and the largest one right below |
| * a new cover node. By default, diff==0 means we'll be inserted |
| * on the right. |
| */ |
| new->node.bit--; /* anticipate cover node insertion */ |
| if (new->node.pfx == old->node.pfx) { |
| new->node.bit = -1; /* mark as new dup tree, just in case */ |
| |
| if (unlikely(eb_gettag(root_right))) { |
| /* we refuse to duplicate this key if the tree is |
| * tagged as containing only unique keys. |
| */ |
| return old; |
| } |
| |
| if (eb_gettag(troot) != EB_LEAF) { |
| /* there was already a dup tree below */ |
| struct eb_node *ret; |
| ret = eb_insert_dup(&old->node, &new->node); |
| return container_of(ret, struct ebmb_node, node); |
| } |
| /* otherwise fall through to insert first duplicate */ |
| } |
| /* otherwise we just rely on the tests below to select the right side */ |
| else if (new->node.pfx < old->node.pfx) |
| diff = -1; /* force insertion to left side */ |
| } |
| |
| insert_above: |
| new_left = eb_dotag(&new->node.branches, EB_LEFT); |
| new_rght = eb_dotag(&new->node.branches, EB_RGHT); |
| new_leaf = eb_dotag(&new->node.branches, EB_LEAF); |
| |
| if (diff >= 0) { |
| new->node.branches.b[EB_LEFT] = troot; |
| new->node.branches.b[EB_RGHT] = new_leaf; |
| new->node.leaf_p = new_rght; |
| *up_ptr = new_left; |
| } |
| else { |
| new->node.branches.b[EB_LEFT] = new_leaf; |
| new->node.branches.b[EB_RGHT] = troot; |
| new->node.leaf_p = new_left; |
| *up_ptr = new_rght; |
| } |
| |
| root->b[side] = eb_dotag(&new->node.branches, EB_NODE); |
| return new; |
| } |
| |
| |
| |
| #endif /* _EBMBTREE_H */ |
| |