| /* |
| * fast fgets() replacement for log parsing |
| * |
| * Copyright 2000-2009 Willy Tarreau <w@1wt.eu> |
| * |
| * This program is free software; you can redistribute it and/or |
| * modify it under the terms of the GNU General Public License |
| * as published by the Free Software Foundation; either version |
| * 2 of the License, or (at your option) any later version. |
| * |
| * This function manages its own buffer and returns a pointer to that buffer |
| * in order to avoid expensive memory copies. It also checks for line breaks |
| * 32 bits at a time. It could be improved a lot using mmap() but we would |
| * not be allowed to replace trailing \n with zeroes and we would be limited |
| * to small log files on 32-bit machines. |
| * |
| */ |
| |
| #include <stdlib.h> |
| #include <string.h> |
| #include <stdio.h> |
| #include <unistd.h> |
| |
| // return 1 if the integer contains at least one zero byte |
| static inline unsigned int has_zero(unsigned int x) |
| { |
| unsigned int y; |
| |
| /* Principle: we want to perform 4 tests on one 32-bit int at once. For |
| * this, we have to simulate an SIMD instruction which we don't have by |
| * default. The principle is that a zero byte is the only one which |
| * will cause a 1 to appear on the upper bit of a byte/word/etc... when |
| * we subtract 1. So we can detect a zero byte if a one appears at any |
| * of the bits 7, 15, 23 or 31 where it was not. It takes only one |
| * instruction to test for the presence of any of these bits, but it is |
| * still complex to check for their initial absence. Thus, we'll |
| * proceed differently : we first save and clear only those bits, then |
| * we check in the final result if one of them is present and was not. |
| */ |
| y = x; |
| x = ~x & 0x80808080; /* save and invert bits 7, 15, 23, 31 */ |
| y &= 0x7F7F7F7F; /* clear them */ |
| y -= 0x01010101; /* generate a carry */ |
| y &= x; /* clear the bits that were already set */ |
| return !!y; |
| } |
| |
| |
| // return 1 if the argument contains at least one zero byte. See principle above. |
| static inline unsigned int has_zero64(unsigned long long x) |
| { |
| unsigned long long y; |
| |
| y = x; |
| x = ~x & 0x8080808080808080ULL; /* save bits 7, 15, 23, 31, 39, 47, 55 and 63 */ |
| y &= 0x7F7F7F7F7F7F7F7FULL; /* clear them */ |
| y -= 0x0101010101010101ULL; /* generate a carry */ |
| y &= x; /* clear the bits that were already set */ |
| return !!y; |
| } |
| |
| #define FGETS2_BUFSIZE (256*1024) |
| const char *fgets2(FILE *stream) |
| { |
| static char buffer[FGETS2_BUFSIZE + 9]; // +9 to have zeroes past the end |
| static char *end = buffer; |
| static char *line = buffer; |
| |
| char *next; |
| int ret; |
| |
| next = line; |
| |
| while (1) { |
| /* this is a speed-up, we read 64 bits at once and check for an |
| * LF character there. We stop if found then continue one at a |
| * time. |
| */ |
| |
| if (next <= (end-12)) { |
| /* max 3 bytes tested here */ |
| while ((((unsigned long)next) & 3) && *next != '\n') |
| next++; |
| |
| /* maybe we have can skip 4 more bytes */ |
| if ((((unsigned long)next) & 4) && !has_zero(*(unsigned int *)next ^ 0x0A0A0A0AU)) |
| next += 4; |
| } |
| |
| /* now next is multiple of 8 or equal to end */ |
| while (next <= (end-68)) { |
| if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL)) |
| break; |
| next += 8; |
| if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL)) |
| break; |
| next += 8; |
| if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL)) |
| break; |
| next += 8; |
| if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL)) |
| break; |
| next += 8; |
| if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL)) |
| break; |
| next += 8; |
| if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL)) |
| break; |
| next += 8; |
| if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL)) |
| break; |
| next += 8; |
| if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL)) |
| break; |
| next += 8; |
| } |
| |
| /* maybe we can skip 4 more bytes */ |
| if (!has_zero(*(unsigned int *)next ^ 0x0A0A0A0AU)) |
| next += 4; |
| |
| /* we finish if needed. Note that next might be slightly higher |
| * than end here because we might have gone past it above. |
| */ |
| while (next < end) { |
| if (*next == '\n') { |
| const char *start = line; |
| |
| *next = '\0'; |
| line = next + 1; |
| return start; |
| } |
| next++; |
| } |
| |
| /* we found an incomplete line. First, let's move the |
| * remaining part of the buffer to the beginning, then |
| * try to complete the buffer with a new read. |
| */ |
| if (line > buffer) { |
| if (end != line) |
| memmove(buffer, line, end - line); |
| end = buffer + (end - line); |
| next = end; |
| line = buffer; |
| } else { |
| if (end == buffer + FGETS2_BUFSIZE) |
| return NULL; |
| } |
| |
| ret = read(fileno(stream), end, buffer + FGETS2_BUFSIZE - end); |
| |
| if (ret <= 0) { |
| if (end == line) |
| return NULL; |
| |
| *end = '\0'; |
| return line; |
| } |
| |
| end += ret; |
| /* search for '\n' again */ |
| } |
| } |
| |
| #ifdef BENCHMARK |
| int main() { |
| const char *p; |
| unsigned int lines = 0; |
| |
| while ((p=fgets2(stdin))) |
| lines++; |
| printf("lines=%d\n", lines); |
| return 0; |
| } |
| #endif |