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wdenk0587dd12002-10-26 17:33:42 +00001/*
2 * (C) Copyright 2001
3 * Wolfgang Denk, DENX Software Engineering, wd@denx.de.
4 *
Wolfgang Denkd79de1d2013-07-08 09:37:19 +02005 * SPDX-License-Identifier: GPL-2.0+
wdenk0587dd12002-10-26 17:33:42 +00006 */
7
8/*
9 * Date & Time support for Philips PCF8563 RTC
10 */
11
12#include <common.h>
13#include <command.h>
Simon Glass2d937bb2015-04-20 12:37:17 -060014#include <errno.h>
wdenk0587dd12002-10-26 17:33:42 +000015#include <rtc.h>
16
Jon Loeligerf7e91252007-07-09 18:10:50 -050017#if defined(CONFIG_CMD_DATE) || defined(CONFIG_TIMESTAMP)
wdenk0587dd12002-10-26 17:33:42 +000018
19#define FEBRUARY 2
20#define STARTOFTIME 1970
21#define SECDAY 86400L
22#define SECYR (SECDAY * 365)
23#define leapyear(year) ((year) % 4 == 0)
Wolfgang Denka1be4762008-05-20 16:00:29 +020024#define days_in_year(a) (leapyear(a) ? 366 : 365)
25#define days_in_month(a) (month_days[(a) - 1])
wdenk0587dd12002-10-26 17:33:42 +000026
27static int month_days[12] = {
28 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31
29};
30
31/*
32 * This only works for the Gregorian calendar - i.e. after 1752 (in the UK)
33 */
Simon Glass2d937bb2015-04-20 12:37:17 -060034int rtc_calc_weekday(struct rtc_time *tm)
wdenk0587dd12002-10-26 17:33:42 +000035{
36 int leapsToDate;
37 int lastYear;
38 int day;
39 int MonthOffset[] = { 0,31,59,90,120,151,181,212,243,273,304,334 };
40
Simon Glass2d937bb2015-04-20 12:37:17 -060041 if (tm->tm_year < 1753)
42 return -EINVAL;
wdenk0587dd12002-10-26 17:33:42 +000043 lastYear=tm->tm_year-1;
44
45 /*
46 * Number of leap corrections to apply up to end of last year
47 */
48 leapsToDate = lastYear/4 - lastYear/100 + lastYear/400;
49
50 /*
51 * This year is a leap year if it is divisible by 4 except when it is
52 * divisible by 100 unless it is divisible by 400
53 *
54 * e.g. 1904 was a leap year, 1900 was not, 1996 is, and 2000 will be
55 */
56 if((tm->tm_year%4==0) &&
57 ((tm->tm_year%100!=0) || (tm->tm_year%400==0)) &&
58 (tm->tm_mon>2)) {
59 /*
60 * We are past Feb. 29 in a leap year
61 */
62 day=1;
63 } else {
64 day=0;
65 }
66
67 day += lastYear*365 + leapsToDate + MonthOffset[tm->tm_mon-1] + tm->tm_mday;
68
69 tm->tm_wday=day%7;
Simon Glass2d937bb2015-04-20 12:37:17 -060070
71 return 0;
wdenk0587dd12002-10-26 17:33:42 +000072}
73
74void to_tm(int tim, struct rtc_time * tm)
75{
76 register int i;
77 register long hms, day;
78
79 day = tim / SECDAY;
80 hms = tim % SECDAY;
81
82 /* Hours, minutes, seconds are easy */
83 tm->tm_hour = hms / 3600;
84 tm->tm_min = (hms % 3600) / 60;
85 tm->tm_sec = (hms % 3600) % 60;
86
87 /* Number of years in days */
88 for (i = STARTOFTIME; day >= days_in_year(i); i++) {
89 day -= days_in_year(i);
90 }
91 tm->tm_year = i;
92
93 /* Number of months in days left */
94 if (leapyear(tm->tm_year)) {
95 days_in_month(FEBRUARY) = 29;
96 }
97 for (i = 1; day >= days_in_month(i); i++) {
98 day -= days_in_month(i);
99 }
100 days_in_month(FEBRUARY) = 28;
101 tm->tm_mon = i;
102
103 /* Days are what is left over (+1) from all that. */
104 tm->tm_mday = day + 1;
105
106 /*
107 * Determine the day of week
108 */
Simon Glass2d937bb2015-04-20 12:37:17 -0600109 rtc_calc_weekday(tm);
wdenk0587dd12002-10-26 17:33:42 +0000110}
111
112/* Converts Gregorian date to seconds since 1970-01-01 00:00:00.
113 * Assumes input in normal date format, i.e. 1980-12-31 23:59:59
114 * => year=1980, mon=12, day=31, hour=23, min=59, sec=59.
115 *
116 * [For the Julian calendar (which was used in Russia before 1917,
117 * Britain & colonies before 1752, anywhere else before 1582,
118 * and is still in use by some communities) leave out the
119 * -year/100+year/400 terms, and add 10.]
120 *
121 * This algorithm was first published by Gauss (I think).
122 *
123 * WARNING: this function will overflow on 2106-02-07 06:28:16 on
124 * machines were long is 32-bit! (However, as time_t is signed, we
125 * will already get problems at other places on 2038-01-19 03:14:08)
126 */
127unsigned long
128mktime (unsigned int year, unsigned int mon,
129 unsigned int day, unsigned int hour,
130 unsigned int min, unsigned int sec)
131{
132 if (0 >= (int) (mon -= 2)) { /* 1..12 -> 11,12,1..10 */
133 mon += 12; /* Puts Feb last since it has leap day */
134 year -= 1;
135 }
136
137 return (((
138 (unsigned long) (year/4 - year/100 + year/400 + 367*mon/12 + day) +
139 year*365 - 719499
140 )*24 + hour /* now have hours */
141 )*60 + min /* now have minutes */
142 )*60 + sec; /* finally seconds */
143}
144
Jon Loeliger07efe2a2007-07-10 10:27:39 -0500145#endif