| /* |
| * Copyright (c) 2013-2020, Arm Limited and Contributors. All rights reserved. |
| * |
| * SPDX-License-Identifier: BSD-3-Clause |
| */ |
| |
| #include <stddef.h> |
| #include <string.h> |
| #include <stdint.h> |
| |
| void *memset(void *dst, int val, size_t count) |
| { |
| uint8_t *ptr = dst; |
| uint64_t *ptr64; |
| uint64_t fill = (unsigned char)val; |
| |
| /* Simplify code below by making sure we write at least one byte. */ |
| if (count == 0U) { |
| return dst; |
| } |
| |
| /* Handle the first part, until the pointer becomes 64-bit aligned. */ |
| while (((uintptr_t)ptr & 7U) != 0U) { |
| *ptr = (uint8_t)val; |
| ptr++; |
| if (--count == 0U) { |
| return dst; |
| } |
| } |
| |
| /* Duplicate the fill byte to the rest of the 64-bit word. */ |
| fill |= fill << 8; |
| fill |= fill << 16; |
| fill |= fill << 32; |
| |
| /* Use 64-bit writes for as long as possible. */ |
| ptr64 = (uint64_t *)ptr; |
| for (; count >= 8U; count -= 8) { |
| *ptr64 = fill; |
| ptr64++; |
| } |
| |
| /* Handle the remaining part byte-per-byte. */ |
| ptr = (uint8_t *)ptr64; |
| while (count-- > 0U) { |
| *ptr = (uint8_t)val; |
| ptr++; |
| } |
| |
| return dst; |
| } |