[IMPORT] import ebtree v5.0 into directory ebtree/
We needed to upgrade ebtree to v5.0 to support string indexing,
and it was getting very painful to have it split across 2 dirs
and to have to patch it. Now we just have to copy the .c and .h
files to the right place.
diff --git a/ebtree/ebmbtree.h b/ebtree/ebmbtree.h
new file mode 100644
index 0000000..947dd5e
--- /dev/null
+++ b/ebtree/ebmbtree.h
@@ -0,0 +1,336 @@
+/*
+ * Elastic Binary Trees - macros and structures for Multi-Byte data nodes.
+ * Version 5.0
+ * (C) 2002-2009 - Willy Tarreau <w@1wt.eu>
+ *
+ * This program is free software; you can redistribute it and/or modify
+ * it under the terms of the GNU General Public License as published by
+ * the Free Software Foundation; either version 2 of the License, or
+ * (at your option) any later version.
+ *
+ * This program is distributed in the hope that it will be useful,
+ * but WITHOUT ANY WARRANTY; without even the implied warranty of
+ * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
+ * GNU General Public License for more details.
+ *
+ * You should have received a copy of the GNU General Public License
+ * along with this program; if not, write to the Free Software
+ * Foundation, Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA
+ */
+
+#include <string.h>
+#include "ebtree.h"
+
+/* Return the structure of type <type> whose member <member> points to <ptr> */
+#define ebmb_entry(ptr, type, member) container_of(ptr, type, member)
+
+#define EBMB_ROOT EB_ROOT
+#define EBMB_TREE_HEAD EB_TREE_HEAD
+
+/* This structure carries a node, a leaf, and a key. It must start with the
+ * eb_node so that it can be cast into an eb_node. We could also have put some
+ * sort of transparent union here to reduce the indirection level, but the fact
+ * is, the end user is not meant to manipulate internals, so this is pointless.
+ * The 'node.bit' value here works differently from scalar types, as it contains
+ * the number of identical bits between the two branches.
+ */
+struct ebmb_node {
+ struct eb_node node; /* the tree node, must be at the beginning */
+ unsigned char key[0]; /* the key, its size depends on the application */
+};
+
+/*
+ * Exported functions and macros.
+ * Many of them are always inlined because they are extremely small, and
+ * are generally called at most once or twice in a program.
+ */
+
+/* Return leftmost node in the tree, or NULL if none */
+static forceinline struct ebmb_node *ebmb_first(struct eb_root *root)
+{
+ return ebmb_entry(eb_first(root), struct ebmb_node, node);
+}
+
+/* Return rightmost node in the tree, or NULL if none */
+static forceinline struct ebmb_node *ebmb_last(struct eb_root *root)
+{
+ return ebmb_entry(eb_last(root), struct ebmb_node, node);
+}
+
+/* Return next node in the tree, or NULL if none */
+static forceinline struct ebmb_node *ebmb_next(struct ebmb_node *ebmb)
+{
+ return ebmb_entry(eb_next(&ebmb->node), struct ebmb_node, node);
+}
+
+/* Return previous node in the tree, or NULL if none */
+static forceinline struct ebmb_node *ebmb_prev(struct ebmb_node *ebmb)
+{
+ return ebmb_entry(eb_prev(&ebmb->node), struct ebmb_node, node);
+}
+
+/* Return next node in the tree, skipping duplicates, or NULL if none */
+static forceinline struct ebmb_node *ebmb_next_unique(struct ebmb_node *ebmb)
+{
+ return ebmb_entry(eb_next_unique(&ebmb->node), struct ebmb_node, node);
+}
+
+/* Return previous node in the tree, skipping duplicates, or NULL if none */
+static forceinline struct ebmb_node *ebmb_prev_unique(struct ebmb_node *ebmb)
+{
+ return ebmb_entry(eb_prev_unique(&ebmb->node), struct ebmb_node, node);
+}
+
+/* Delete node from the tree if it was linked in. Mark the node unused. Note
+ * that this function relies on a non-inlined generic function: eb_delete.
+ */
+static forceinline void ebmb_delete(struct ebmb_node *ebmb)
+{
+ eb_delete(&ebmb->node);
+}
+
+/* The following functions are not inlined by default. They are declared
+ * in ebmbtree.c, which simply relies on their inline version.
+ */
+REGPRM3 struct ebmb_node *ebmb_lookup(struct eb_root *root, const void *x, unsigned int len);
+REGPRM3 struct ebmb_node *ebmb_insert(struct eb_root *root, struct ebmb_node *new, unsigned int len);
+
+/* The following functions are less likely to be used directly, because their
+ * code is larger. The non-inlined version is preferred.
+ */
+
+/* Delete node from the tree if it was linked in. Mark the node unused. */
+static forceinline void __ebmb_delete(struct ebmb_node *ebmb)
+{
+ __eb_delete(&ebmb->node);
+}
+
+/* Find the first occurence of a key of <len> bytes in the tree <root>.
+ * If none can be found, return NULL.
+ */
+static forceinline struct ebmb_node *__ebmb_lookup(struct eb_root *root, const void *x, unsigned int len)
+{
+ struct ebmb_node *node;
+ eb_troot_t *troot;
+ unsigned int bit;
+
+ troot = root->b[EB_LEFT];
+ if (unlikely(troot == NULL))
+ return NULL;
+
+ bit = 0;
+ while (1) {
+ if ((eb_gettag(troot) == EB_LEAF)) {
+ node = container_of(eb_untag(troot, EB_LEAF),
+ struct ebmb_node, node.branches);
+ if (memcmp(node->key, x, len) == 0)
+ return node;
+ else
+ return NULL;
+ }
+ node = container_of(eb_untag(troot, EB_NODE),
+ struct ebmb_node, node.branches);
+
+ if (node->node.bit < 0) {
+ /* We have a dup tree now. Either it's for the same
+ * value, and we walk down left, or it's a different
+ * one and we don't have our key.
+ */
+ if (memcmp(node->key, x, len) != 0)
+ return NULL;
+
+ troot = node->node.branches.b[EB_LEFT];
+ while (eb_gettag(troot) != EB_LEAF)
+ troot = (eb_untag(troot, EB_NODE))->b[EB_LEFT];
+ node = container_of(eb_untag(troot, EB_LEAF),
+ struct ebmb_node, node.branches);
+ return node;
+ }
+
+ /* OK, normal data node, let's walk down */
+ bit = equal_bits(x, node->key, bit, node->node.bit);
+ if (bit < node->node.bit)
+ return NULL; /* no more common bits */
+
+ troot = node->node.branches.b[(((unsigned char*)x)[node->node.bit >> 3] >>
+ (~node->node.bit & 7)) & 1];
+ }
+}
+
+/* Insert ebmb_node <new> into subtree starting at node root <root>.
+ * Only new->key needs be set with the key. The ebmb_node is returned.
+ * If root->b[EB_RGHT]==1, the tree may only contain unique keys. The
+ * len is specified in bytes.
+ */
+static forceinline struct ebmb_node *
+__ebmb_insert(struct eb_root *root, struct ebmb_node *new, unsigned int len)
+{
+ struct ebmb_node *old;
+ unsigned int side;
+ eb_troot_t *troot;
+ eb_troot_t *root_right = root;
+ int diff;
+ int bit;
+
+ side = EB_LEFT;
+ troot = root->b[EB_LEFT];
+ root_right = root->b[EB_RGHT];
+ if (unlikely(troot == NULL)) {
+ /* Tree is empty, insert the leaf part below the left branch */
+ root->b[EB_LEFT] = eb_dotag(&new->node.branches, EB_LEAF);
+ new->node.leaf_p = eb_dotag(root, EB_LEFT);
+ new->node.node_p = NULL; /* node part unused */
+ return new;
+ }
+
+ len <<= 3;
+
+ /* The tree descent is fairly easy :
+ * - first, check if we have reached a leaf node
+ * - second, check if we have gone too far
+ * - third, reiterate
+ * Everywhere, we use <new> for the node node we are inserting, <root>
+ * for the node we attach it to, and <old> for the node we are
+ * displacing below <new>. <troot> will always point to the future node
+ * (tagged with its type). <side> carries the side the node <new> is
+ * attached to below its parent, which is also where previous node
+ * was attached.
+ */
+
+ bit = 0;
+ while (1) {
+ if (unlikely(eb_gettag(troot) == EB_LEAF)) {
+ eb_troot_t *new_left, *new_rght;
+ eb_troot_t *new_leaf, *old_leaf;
+
+ old = container_of(eb_untag(troot, EB_LEAF),
+ struct ebmb_node, node.branches);
+
+ new_left = eb_dotag(&new->node.branches, EB_LEFT);
+ new_rght = eb_dotag(&new->node.branches, EB_RGHT);
+ new_leaf = eb_dotag(&new->node.branches, EB_LEAF);
+ old_leaf = eb_dotag(&old->node.branches, EB_LEAF);
+
+ new->node.node_p = old->node.leaf_p;
+
+ /* Right here, we have 3 possibilities :
+ * - the tree does not contain the key, and we have
+ * new->key < old->key. We insert new above old, on
+ * the left ;
+ *
+ * - the tree does not contain the key, and we have
+ * new->key > old->key. We insert new above old, on
+ * the right ;
+ *
+ * - the tree does contain the key, which implies it
+ * is alone. We add the new key next to it as a
+ * first duplicate.
+ *
+ * The last two cases can easily be partially merged.
+ */
+ bit = equal_bits(new->key, old->key, bit, len);
+ diff = cmp_bits(new->key, old->key, bit);
+
+ if (diff < 0) {
+ new->node.leaf_p = new_left;
+ old->node.leaf_p = new_rght;
+ new->node.branches.b[EB_LEFT] = new_leaf;
+ new->node.branches.b[EB_RGHT] = old_leaf;
+ } else {
+ /* we may refuse to duplicate this key if the tree is
+ * tagged as containing only unique keys.
+ */
+ if (diff == 0 && eb_gettag(root_right))
+ return old;
+
+ /* new->key >= old->key, new goes the right */
+ old->node.leaf_p = new_left;
+ new->node.leaf_p = new_rght;
+ new->node.branches.b[EB_LEFT] = old_leaf;
+ new->node.branches.b[EB_RGHT] = new_leaf;
+
+ if (diff == 0) {
+ new->node.bit = -1;
+ root->b[side] = eb_dotag(&new->node.branches, EB_NODE);
+ return new;
+ }
+ }
+ break;
+ }
+
+ /* OK we're walking down this link */
+ old = container_of(eb_untag(troot, EB_NODE),
+ struct ebmb_node, node.branches);
+
+ /* Stop going down when we don't have common bits anymore. We
+ * also stop in front of a duplicates tree because it means we
+ * have to insert above. Note: we can compare more bits than
+ * the current node's because as long as they are identical, we
+ * know we descend along the correct side.
+ */
+ if (old->node.bit < 0) {
+ /* we're above a duplicate tree, we must compare till the end */
+ bit = equal_bits(new->key, old->key, bit, len);
+ goto dup_tree;
+ }
+ else if (bit < old->node.bit) {
+ bit = equal_bits(new->key, old->key, bit, old->node.bit);
+ }
+
+ if (bit < old->node.bit) { /* we don't have all bits in common */
+ /* The tree did not contain the key, so we insert <new> before the node
+ * <old>, and set ->bit to designate the lowest bit position in <new>
+ * which applies to ->branches.b[].
+ */
+ eb_troot_t *new_left, *new_rght;
+ eb_troot_t *new_leaf, *old_node;
+
+ dup_tree:
+ new_left = eb_dotag(&new->node.branches, EB_LEFT);
+ new_rght = eb_dotag(&new->node.branches, EB_RGHT);
+ new_leaf = eb_dotag(&new->node.branches, EB_LEAF);
+ old_node = eb_dotag(&old->node.branches, EB_NODE);
+
+ new->node.node_p = old->node.node_p;
+
+ diff = cmp_bits(new->key, old->key, bit);
+ if (diff < 0) {
+ new->node.leaf_p = new_left;
+ old->node.node_p = new_rght;
+ new->node.branches.b[EB_LEFT] = new_leaf;
+ new->node.branches.b[EB_RGHT] = old_node;
+ }
+ else if (diff > 0) {
+ old->node.node_p = new_left;
+ new->node.leaf_p = new_rght;
+ new->node.branches.b[EB_LEFT] = old_node;
+ new->node.branches.b[EB_RGHT] = new_leaf;
+ }
+ else {
+ struct eb_node *ret;
+ ret = eb_insert_dup(&old->node, &new->node);
+ return container_of(ret, struct ebmb_node, node);
+ }
+ break;
+ }
+
+ /* walk down */
+ root = &old->node.branches;
+ side = (new->key[old->node.bit >> 3] >> (~old->node.bit & 7)) & 1;
+ troot = root->b[side];
+ }
+
+ /* Ok, now we are inserting <new> between <root> and <old>. <old>'s
+ * parent is already set to <new>, and the <root>'s branch is still in
+ * <side>. Update the root's leaf till we have it. Note that we can also
+ * find the side by checking the side of new->node.node_p.
+ */
+
+ /* We need the common higher bits between new->key and old->key.
+ * This number of bits is already in <bit>.
+ */
+ new->node.bit = bit;
+ root->b[side] = eb_dotag(&new->node.branches, EB_NODE);
+ return new;
+}
+