Add 'list' command to repo.
This isn't a required command, but might be more discoverable for
repo newbies?
Change-Id: If357346f234774d42e04e024e65acdaf6dca6c62
diff --git a/subcmds/list.py b/subcmds/list.py
new file mode 100644
index 0000000..2be8257
--- /dev/null
+++ b/subcmds/list.py
@@ -0,0 +1,48 @@
+#
+# Copyright (C) 2011 The Android Open Source Project
+#
+# Licensed under the Apache License, Version 2.0 (the "License");
+# you may not use this file except in compliance with the License.
+# You may obtain a copy of the License at
+#
+# http://www.apache.org/licenses/LICENSE-2.0
+#
+# Unless required by applicable law or agreed to in writing, software
+# distributed under the License is distributed on an "AS IS" BASIS,
+# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
+# See the License for the specific language governing permissions and
+# limitations under the License.
+
+from command import Command, MirrorSafeCommand
+
+class List(Command, MirrorSafeCommand):
+ common = True
+ helpSummary = "List projects and their associated directories"
+ helpUsage = """
+%prog [<project>...]
+"""
+ helpDescription = """
+List all projects; pass '.' to list the project for the cwd.
+
+This is similar to running: repo forall -c 'echo "$REPO_PATH : $REPO_PROJECT"'.
+"""
+
+ def Execute(self, opt, args):
+ """List all projects and the associated directories.
+
+ This may be possible to do with 'repo forall', but repo newbies have
+ trouble figuring that out. The idea here is that it should be more
+ discoverable.
+
+ Args:
+ opt: The options. We don't take any.
+ args: Positional args. Can be a list of projects to list, or empty.
+ """
+ projects = self.GetProjects(args)
+
+ lines = []
+ for project in projects:
+ lines.append("%s : %s" % (project.relpath, project.name))
+
+ lines.sort()
+ print '\n'.join(lines)