malloc: Fix memalign not honoring alignment prior to full malloc init
When using memalign() in a scenario where U-Boot is configured for full
malloc support with simple malloc not explicitly enabled and before the
full malloc support is initialized, a memory block is being allocated
and returned without the alignment parameter getting honored.
Fix this issue by replacing the existing memalign pre-full malloc init
logic with a call to memalign_simple() this way ensuring proper alignment
of the returned memory block.
Fixes: ee038c58d519 ("malloc: Use malloc simple before malloc is fully initialized in memalign()")
Signed-off-by: Andreas Dannenberg <dannenberg@ti.com>
Reviewed-by: Lokesh Vutla <lokeshvutla@ti.com>
diff --git a/common/dlmalloc.c b/common/dlmalloc.c
index edaad29..6f12a18 100644
--- a/common/dlmalloc.c
+++ b/common/dlmalloc.c
@@ -1893,8 +1893,7 @@
#if CONFIG_VAL(SYS_MALLOC_F_LEN)
if (!(gd->flags & GD_FLG_FULL_MALLOC_INIT)) {
- nb = roundup(bytes, alignment);
- return malloc_simple(nb);
+ return memalign_simple(alignment, bytes);
}
#endif
diff --git a/include/malloc.h b/include/malloc.h
index b714fed..5efa692 100644
--- a/include/malloc.h
+++ b/include/malloc.h
@@ -878,7 +878,6 @@
#define memalign memalign_simple
static inline void free(void *ptr) {}
void *calloc(size_t nmemb, size_t size);
-void *memalign_simple(size_t alignment, size_t bytes);
void *realloc_simple(void *ptr, size_t size);
void malloc_simple_info(void);
#else
@@ -914,6 +913,7 @@
/* Simple versions which can be used when space is tight */
void *malloc_simple(size_t size);
+void *memalign_simple(size_t alignment, size_t bytes);
#pragma GCC visibility push(hidden)
# if __STD_C