lmb: Remove lmb_alloc_base_flags()
lmb_alloc_base() is just calling lmb_alloc_base_flags() with LMB_NONE.
There's not much we gain from this abstraction, so let's remove the
former add the flags argument to lmb_alloc_base() and make the code
a bit easier to follow.
Reviewed-by: Sam Protsenko <semen.protsenko@linaro.org>
Tested-by: Sam Protsenko <semen.protsenko@linaro.org>
Signed-off-by: Ilias Apalodimas <ilias.apalodimas@linaro.org>
diff --git a/test/lib/lmb.c b/test/lib/lmb.c
index 971614f..fcb5f1a 100644
--- a/test/lib/lmb.c
+++ b/test/lib/lmb.c
@@ -128,7 +128,7 @@
ASSERT_LMB(mem_lst, used_lst, 0, 0, 2, alloc_64k_addr, 0x10000,
ram_end - 4, 4, 0, 0);
/* alloc below end of reserved region -> below reserved region */
- b = lmb_alloc_base(4, 1, alloc_64k_end);
+ b = lmb_alloc_base(4, 1, alloc_64k_end, LMB_NONE);
ut_asserteq(b, alloc_64k_addr - 4);
ASSERT_LMB(mem_lst, used_lst, 0, 0, 2,
alloc_64k_addr - 4, 0x10000 + 4, ram_end - 4, 4, 0, 0);
@@ -138,7 +138,7 @@
ut_asserteq(c, ram_end - 8);
ASSERT_LMB(mem_lst, used_lst, 0, 0, 2,
alloc_64k_addr - 4, 0x10000 + 4, ram_end - 8, 8, 0, 0);
- d = lmb_alloc_base(4, 1, alloc_64k_end);
+ d = lmb_alloc_base(4, 1, alloc_64k_end, LMB_NONE);
ut_asserteq(d, alloc_64k_addr - 8);
ASSERT_LMB(mem_lst, used_lst, 0, 0, 2,
alloc_64k_addr - 8, 0x10000 + 8, ram_end - 8, 8, 0, 0);
@@ -163,7 +163,7 @@
alloc_64k_addr - 8, 4, alloc_64k_addr, 0x10000,
ram_end - 8, 4);
/* allocate again to ensure we get the same address */
- b2 = lmb_alloc_base(4, 1, alloc_64k_end);
+ b2 = lmb_alloc_base(4, 1, alloc_64k_end, LMB_NONE);
ut_asserteq(b, b2);
ASSERT_LMB(mem_lst, used_lst, 0, 0, 2,
alloc_64k_addr - 8, 0x10000 + 8, ram_end - 8, 4, 0, 0);
@@ -363,7 +363,7 @@
ASSERT_LMB(mem_lst, used_lst, ram, ram_size, 0, 0, 0, 0, 0, 0, 0);
/* allocate a block with base*/
- b = lmb_alloc_base(alloc_size, align, ram_end);
+ b = lmb_alloc_base(alloc_size, align, ram_end, LMB_NONE);
ut_assert(a == b);
ASSERT_LMB(mem_lst, used_lst, ram, ram_size, 1,
ram + ram_size - alloc_size_aligned,