tools/Makefile: suppress "which swig" error output
The Makefile in tools/ tries to find the "swig" utility by calling "which".
If nothing is found in the path, some versions of which will print an error
message:
$ make clean
which: no swig in (/usr/local/bin:/usr/bin:/bin)
This does not apply to all version of "which", though:
$ echo $0
bash
$ type which
which is aliased to `type -path'
$ which foo <== this version is OK
$ /usr/bin/which foo <== this one is chatty
/usr/bin/which: no foo in (/usr/local/bin:/usr/bin:/bin)
$ sh <== make uses /bin/sh
sh-4.3$ which foo <== no alias here
which: no foo in (/usr/local/bin:/usr/bin:/bin)
This error message is rather pointless in our case, since we just have
this very check to care for this. So add stderr redirection to suppress
the message.
Signed-off-by: Andre Przywara <andre.przywara@arm.com>
Reviewed-by: Simon Glass <sjg@chromium.org>
diff --git a/tools/Makefile b/tools/Makefile
index 9edb504..5b81dde 100644
--- a/tools/Makefile
+++ b/tools/Makefile
@@ -112,7 +112,7 @@
# Build a libfdt Python module if swig is available
# Use 'sudo apt-get install swig libpython-dev' to enable this
hostprogs-$(CONFIG_SPL_OF_PLATDATA) += \
- $(if $(shell which swig),_libfdt.so)
+ $(if $(shell which swig 2> /dev/null),_libfdt.so)
_libfdt.so-sharedobjs += $(LIBFDT_OBJS)
libfdt: